Advertisements
Advertisements
प्रश्न
Prove that EV = Δ = ∇E
आकृति
योग
उत्तर
E∇ = EE–1Δ .......[∵ ∇ = E–1Δ]
= Δ .......(1)
∇E = E–1ΔE
= E–1EΔ
= Δ .......(2)
From (1) and (2)
E∇ = Δ = ∇E
shaalaa.com
Finite Differences
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
If h = 1 then prove that (E–1Δ)x3 = 3x2 – 3x + 1
If f(x) = x2 + 3x than show that Δf(x) = 2x + 4
Evaluate Δ`[1/((x + 1)(x + 2))]` by taking ‘1’ as the interval of differencing
Find the missing entry in the following table
| x | 0 | 1 | 2 | 3 | 4 |
| yx | 1 | 3 | 9 | - | 81 |
Following are the population of a district
| Year (x) | 1881 | 1891 | 1901 | 1911 | 1921 | 1931 |
| Population (y) Thousands |
363 | 391 | 421 | - | 467 | 501 |
Find the population of the year 1911
Choose the correct alternative:
Δf(x) =
Choose the correct alternative:
If h = 1, then Δ(x2) =
Choose the correct alternative:
If c is a constant then Δc =
Choose the correct alternative:
If ‘n’ is a positive integer Δn[Δ-n f(x)]
Prove that Δ∇ = Δ – ∇
