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प्रश्न
Prove that the following number is irrational: √3 + √2
उत्तर
√3 + √2
Let √3 + √2 be a rational number.
⇒ √3 + √2 = x
Squaring on both the sides, we get
( √3 + √2 )2 = x2
⇒ 3 + 2 + 2 x √3 x √2 = x2
⇒ x2 - 5 = 2√6
⇒ √6 = `[ x^2 - 5 ]/2`
Here, x is a rational number.
⇒ x2 is a rational number.
⇒ x2 - 5 is a rational number.
⇒ `[ x^2 - 5]/2` is also a rational number.
But √6 is an irrational number.
⇒ `[ x^2 - 5]/2` is also a irrational number.
⇒ x2 - 5 is an irrational number.
⇒ x2 is an irrational number.
⇒ x is an irrational number.
But we have assume that x is a rational number.
∴ we arrive at a contradiction.
So, our assumption that √3 + √2 is a rational number is wrong.
∴ √3 + √2 is an irrational number.
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