हिंदी

Rate of cooling of a body is 0.4 °C/min when excess temperature is 20 °C. The proportionality constant is ______. -

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प्रश्न

Rate of cooling of a body is 0.4 °C/min when excess temperature is 20 °C. The proportionality constant is ______.

विकल्प

  • 0.01/min

  • 0.02/min

  • 0.03/min

  • 0.04/min

MCQ
रिक्त स्थान भरें

उत्तर

Rate of cooling of a body is 0.4 °C/min when excess temperature is 20 °C. The proportionality constant is 0.02/min.

Explanation:

`("d"theta)/"dt" =  k(theta - theta_0)`

` "k" = 0.4/20` = 0.02/min

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Newton’s Law of Cooling
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