Question

Rate of cooling of a body is 0.4 °C/min when excess temperature is 20 °C. The proportionality constant is ______.

पर्याय

• 0.01/min

• 0.02/min

• 0.03/min

• 0.04/min

Answer 1

Rate of cooling of a body is 0.4 °C/min when excess temperature is 20 °C. The proportionality constant is 0.02/min.

Explanation:

`("d"theta)/"dt" =  k(theta - theta_0)`

` "k" = 0.4/20` = 0.02/min