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प्रश्न
Represent the following inequalities on real number line:
–5 < x ≤ –1
उत्तर
–5 < x ≤ –1
Solution on number line is
संबंधित प्रश्न
Solve the following inequation and write the solution set:
13x – 5 < 15x + 4 < 7x + 12, x ∈ R
Represent the solution on a real number line.
Solve the following in equation and represent the solution set on the number line.
`R - 3 < -1/2 - (2x)/3 <= 5/6, x ∈ R`
Use the real number line to find the range of values of x for which:
x < 0 and –3 ≤ x < 1
Given that x ∈ I. solve the inequation and graph the solution on the number line:
`3 >= (x - 4)/2 + x/3 >= 2`
Solve the following linear in-equation and graph the solution set on a real number line:
3(5x+ 3) ≥ 2(9x-17), x ∈ W
Solve the following linear in-equation and graph the solution set on a real number line:
2(3x-5) > 5(13-2x), x ∈ W
Solve the following linear in-equation and graph the solution set on a real number line :
3x - 9 ≤ 4x - 7 < 2x + 5, x ∈ R
Graph the solution set for each inequality:
-3≤ x ≤3.
Find the range of values of a, which satisfy 7 ≤ – 4x + 2 < 12, x ∈ R. Graph these values of a on the real number line.
For the replacement set = {– 8, – 6, – 4, – 2, 0, 2, 4, 6, 8}, which of the following is not a solution set?
