Advertisements
Advertisements
प्रश्न
Use the real number line to find the range of values of x for which:
x < 0 and –3 ≤ x < 1
उत्तर
x < 0 and –3 ≤ x < 1
Both the given in equations are true in the range where their graphs on the real number lines overlap.
The graphs of the given in equations can be drawn as:
x < 0
–3 ≤ x < 1
From both graphs, it is clear that their common range is –3 ≤ x < 0
APPEARS IN
संबंधित प्रश्न
Find the values of x, which satisfy the inequation `-2 5/6 < 1/2 - (2x)/3 ≤ 2, x ∈ W`. Graph the solution set on the number line.
Represent the solution of the following inequalities on the real number line:
x + 3 ≤ 2x + 9
Given A = {x : –1 < x ≤ 5, x ∈ R} and B = {x : – 4 ≤ x < 3, x ∈ R}
Represent on different number lines:
A' ∩ B
Given A = {x : –1 < x ≤ 5, x ∈ R} and B = {x : – 4 ≤ x < 3, x ∈ R}
Represent on different number lines:
A – B
Solve the following linear in-equation and graph the solution set on a real number line :
3x - 9 ≤ 4x - 7 < 2x + 5, x ∈ R
Give that x ∈ I. Solve the inequation and graph the solution on the number line:
`3≥(x - 4)/(2)+x/(3)≥2`
Graph the solution set for each inequality:
5 ≤ x < 10
Solve the following inequalities and represent the solution on a number line:
2x + 3 < 5
Solve the following inequalities and represent the solution set on a number line:
`0 ≤ (3 - 2x)/(4) ≤ 1`
The following number line represents:
