Advertisements
Advertisements
Question
Use the real number line to find the range of values of x for which:
x < 0 and –3 ≤ x < 1
Solution
x < 0 and –3 ≤ x < 1
Both the given in equations are true in the range where their graphs on the real number lines overlap.
The graphs of the given in equations can be drawn as:
x < 0
–3 ≤ x < 1
From both graphs, it is clear that their common range is –3 ≤ x < 0
APPEARS IN
RELATED QUESTIONS
Solve the following inequation, write the solution set and represent it on the number line.
`-3(x - 7) >= 15 - 7x > (x+1)/3`, x ∉ R
Represent the following inequalities on real number line:
2x – 1 < 5
Represent the following inequalities on real number line:
2(2x – 3) ≤ 6
Represent the following inequalities on real number line:
8 ≥ x > – 3
Represent the solution of the following inequalities on the real number line:
4x – 1 > x + 11
Solve the following linear in-equation and graph the solution set on a real number line:
2x - 11≤ 7 - 3x, x ∈ N
Solve the following inequalities and represent the solution on a number line:
2x - 3 > 5x + 4
Solve the following inequalities and represent the solution set on a number line:
-4 ≤ 2x - 3 ≤ 5
Solve `(2x + 1)/(2) + 2(3 - x) ≥ 7, x ∈ "R"`. Also graph the solution set on the number line
Solve the given inequation and graph the solution on the number line : 2y – 3 < y + 1 ≤ 4y + 7; y ∈ R.