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प्रश्न
S and S are the focii of the ellipse `x^2/a^2 + y^2/b^2 - 1` whose one of the ends of the minor axis is the point B If ∠SBS' = 90°, then the eccentricity of the ellipse is
विकल्प
`1/2`
`1/sqrt(2)`
`1/(2sqrt(2))`
`1/(2sqrt(3))`
MCQ
उत्तर
`1/sqrt(2)`
Explanation:
∴ ∠SBS' = 90° ⇒ BS2 + BS'2 = SS'2
∴ `(sqrt(a^2e^2 + b^2))^2 + (sqrt(a^2e^2 + b^2))^2 = (2ae)^2`
⇒ `e^2 = b^2/a^2`
Also, `e^2 = 1 - b^2/a^2 = 1 - e^2`
⇒ `2e^2 = 1`
⇒ `e = 1/sqrt(2)`
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