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S and S are the focii of the ellipse x2a2+y2b2-1 whose one of the ends of the minor axis is the point B If ∠SBS' = 90°, then the eccentricity of the ellipse is -

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Question

S and S are the focii of the ellipse `x^2/a^2 + y^2/b^2 - 1` whose one of the ends of the minor axis is the point B If ∠SBS' = 90°, then the eccentricity of the ellipse is

Options

  • `1/2`

  • `1/sqrt(2)`

  • `1/(2sqrt(2))`

  • `1/(2sqrt(3))`

MCQ

Solution

`1/sqrt(2)`

Explanation:


∴ ∠SBS' = 90° ⇒ BS2 + BS'2 = SS'2

∴ `(sqrt(a^2e^2 + b^2))^2 + (sqrt(a^2e^2 + b^2))^2 = (2ae)^2`

⇒ `e^2 = b^2/a^2`

Also, `e^2 = 1 - b^2/a^2 = 1 - e^2`

⇒ `2e^2 = 1`

⇒ `e = 1/sqrt(2)`

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