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प्रश्न
Show how you would connect three resistors each of resistance 6 Ω, so that the combination has a resistance of 9 Ω. Also justify your answer.
संख्यात्मक
उत्तर
First, we connect two resistors, each of 6 Ω in parallel connection
then, `1/"R" = 1/6 + 1/6`
= `2/6`
=`1/3`
R = 3 Ω
If the 3rd resistor of 6 Ω and 3 Ω are connected in series, then the resultant resistance
= 6 Ω + 3 Ω
= 9 Ω
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