Question

Show how you would connect three resistors each of resistance 6 Ω, so that the combination has a resistance of 9 Ω. Also justify your answer.

Answer 1

First, we connect two resistors, each of 6 Ω in parallel connection

then, `1/"R" = 1/6 + 1/6`

= `2/6`

=`1/3`

R = 3 Ω

If the 3rd resistor of 6 Ω and 3 Ω are connected in series, then the resultant resistance

= 6 Ω + 3 Ω

= 9 Ω