Advertisements
Advertisements
प्रश्न
Show that the following numbers are irrational.
उत्तर
Let us assume that `6+sqrt2 ` is rational. Then , there exist positive co primes a and b such that
`6+sqrt2=a/b`
`sqrt2=a/b-6`
`sqrt2=(a-6b)/b`
Here we see that `sqrt2` is a rational number which is a contradiction as we know that `sqrt2` is an irrational number
Hence `6+sqrt2`is irrational
APPEARS IN
संबंधित प्रश्न
Show that any positive integer which is of the form 6q + 1 or 6q + 3 or 6q + 5 is odd, where q is some integer.
Use Euclid's Division Algorithm to show that the cube of any positive integer is either of the 9m, 9m + 1 or 9m + 8 for some integer m
Prove that the square of any positive integer is of the form 4q or 4q + 1 for some integer q.
Using Euclid’s algorithm, find the HCF of 405 and 2520 .
Using prime factorization, find the HCF and LCM of 96, 404 In case verify that HCF × LCM = product of given numbers.
Using prime factorization, find the HCF and LCM of 144, 198 In case verify that HCF × LCM = product of given numbers.
Using prime factorization, find the HCF and LCM of 17,23,29 .
Find the simplest form of `368 /496` .
If a and b are two prime numbers then find the HCF(a, b)
If n is a natural number, then 92n − 42n is always divisible by ______.