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Show that the Following Numbers Are Irrational. 6 + √ 2 - Mathematics

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प्रश्न

Show that the following numbers are irrational.

\[6 + \sqrt{2}\]
संख्यात्मक

उत्तर

Let us assume that `6+sqrt2 ` is rational. Then , there exist positive co primes a and b such that

`6+sqrt2=a/b`

`sqrt2=a/b-6`

`sqrt2=(a-6b)/b`

Here we see that `sqrt2` is a rational number which is a contradiction as we know that `sqrt2` is an irrational number

Hence `6+sqrt2`is irrational

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पाठ 1: Real Numbers - Exercise 1.5 [पृष्ठ ४९]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 1 Real Numbers
Exercise 1.5 | Q 1.3 | पृष्ठ ४९

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