Advertisements
Advertisements
प्रश्न
Show that the value of x3 – 8x2 + 12x – 5 is zero, when x = 1.
उत्तर
x3 – 8x2 + 12x – 5
= (1)3 − 8(1)2 + 12(1) − 5
= 1 − 8 + 12 − 5
= 13 − 13
= 0
Hence proved.
APPEARS IN
संबंधित प्रश्न
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
d ÷ x = ..................
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
b + z − d = ....................
If x = 2, y = 5 and z = 4, find the value of the following:
`"xz"/"yz"`
Evaluate:
5x + (3x + 7x)
Evaluate:
6m – (4m – m)
Simplify:
4x + 3 (2x − 5y)
If x = 3, y = 2 and z = 1; find the value of xy
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find Q + P
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find P – Q + R
Simplify:
2 (3x2 – 4x – 8) – (3 – 5x – 2x2)