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प्रश्न
Show that the value of x3 – 8x2 + 12x – 5 is zero, when x = 1.
बेरीज
उत्तर
x3 – 8x2 + 12x – 5
= (1)3 − 8(1)2 + 12(1) − 5
= 1 − 8 + 12 − 5
= 13 − 13
= 0
Hence proved.
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