Advertisements
Advertisements
प्रश्न
Find the value of 3x3 – 4x2 + 5x – 6, when x = − 1.
बेरीज
उत्तर
3x3 – 4x2 + 5x – 6
= 3(− 1)3 − 4(− 1)2 + 5(− 1) − 6
= 3 × − 1 − 4 × 1 − 5 − 6
= − 3 − 4 − 5 − 6
= − 18
shaalaa.com
Concept of Substitution
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
d ÷ x = ..................
State true and false:
`(2"x"-4)/("x"+1)` = − 1, when x = 1
Evaluate:
(9a – 3a) + 4a
Simplify:
a − (a − b − c)
Simplify:
x − (y − z) + x + (y − z) + y − (z + x)
Insert the bracket as indicated:
x2 − y2 + z2 = x2 − (..................)
Insert the bracket as indicated:
m2 + x2 − p2 = − (...................)
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find P – Q
Multiply and then evaluate:
(4x + y) and (x – 2y); when x = 2 and y = 1.
If x = − 3, find the value of 2x3 + 8x2 – 15.