Advertisements
Advertisements
प्रश्न
Shweta's age is six times that of Jayeeta's age. 15 years hence Shweta will be three times as old as Jayeeta; find their ages.
उत्तर
Let Jayeeta's age be x years and Shweta's age be 6x years.
15 years hence, means after 15years.
As per the given condition,
6x + 15 = 3(x + 15)
⇒ 6x + 15 = x + 45
⇒ 3x = 30
⇒ x = 10
Jayeeta's age = x years = 10 years
Shweta's age = 6x = 6(10) = 60 years
Hence, Jayeeta's age is 10 years and Shweeta's age is 60 years.
APPEARS IN
संबंधित प्रश्न
Solve the following equation:
`3"a" - 1/5 = "a"/5 + 5 2/5`
Solve the following equation:
`("2x" - 13)/5 - ("x" - 3)/11 = ("x" - 9)/5 + 1`
Solve the following equation:
5x – 1 = 74
0.4x – 1.2 = 0.3x + 0.6
Solve: y + 20% of y = 18
Find a number whose one-third part exceeds its one-fifth part by 20.
A man is four times as old as his son. After 20 years, he will be twice as old as his son at that time. Find their present ages.
Solve the following equations for the unknown: 15y - 20 = 2y + 6
Solve the following equations for the unknown: `11 - (3)/x = (5)/x + 3`
A man is double his son's age. Twenty years ago, he was six times his son's age. Find the present age of the father and the son.