Advertisements
Advertisements
Question
Shweta's age is six times that of Jayeeta's age. 15 years hence Shweta will be three times as old as Jayeeta; find their ages.
Solution
Let Jayeeta's age be x years and Shweta's age be 6x years.
15 years hence, means after 15years.
As per the given condition,
6x + 15 = 3(x + 15)
⇒ 6x + 15 = x + 45
⇒ 3x = 30
⇒ x = 10
Jayeeta's age = x years = 10 years
Shweta's age = 6x = 6(10) = 60 years
Hence, Jayeeta's age is 10 years and Shweeta's age is 60 years.
APPEARS IN
RELATED QUESTIONS
Solve the following equation:
`"3x"/4 - 1/4("x" - 20) = "x"/4 + 32`
Solve: x – 30% of x = 35
Solve: `(3"x" - 2)/7 - ("x" - 2)/4 = 2`
One-fifth of a number is 5, find the number.
Solve the following equation for the unknown: `x/(2) + x/(4) + x/(8)` = 7
Two numbers are in the ratio 11:13. If the smaller number is 286, find the bigger one.
In a two digit number, the ratio of the digits at the unit's place and the ten's place is 3:2. If the digits are reversed, the resulting number is 27 more than the original number. Find the two digit number.
The ages of P and Q are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their ages.
What number increased by 8% of itself gives 1620?
In a factory male workers are paid one and a half times more than their female counterparts for each hour of work. In a particular week a husband and wife team worked for a total of 60 hours with the husband working twice as much as his wife. The total amount earned by both is Rs 960. If the husband's earning is 4 times that of his wife, find the number of hours each worked.