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प्रश्न
Side of a triangle is given, determine it is a right triangle.
`(2a – 1) cm, 2\sqrt { 2a } cm, and (2a + 1) cm`
योग
उत्तर
Let p = (2a – 1) cm, `q = 2\sqrt { 2a }` cm and r = (2a + 1) cm.
Then,
`(p^2 + q^2 ) = (2a – 1)^2 cm^2 + (2 )^2 cm^2`
`= {(4a^2 + 1– 4a) + 8a}cm^2`
= (4a2 + 4a + 1)cm2
`= (2a + 1)^2 cm^2 = r^2 .`
`(p^2 + q^2 ) = r^2 .`
Hence, the given triangle is right angled
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