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Simplify first three terms in the expansion of the following (2-3x)13 - Mathematics and Statistics

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प्रश्न

Simplify first three terms in the expansion of the following

`(2 - 3x)^(1/3)`

योग

उत्तर

`(2 - 3x)^(1/3)`

= `[2(1 - (3x)/2)]^(1/3)`

= `2^(1/3)(1 - (3x)/2)^(1/3)`

= `2^(1/3)[1 - (1/3)((3x)/2) + ((1/3)(1/3 - 1))/(2!) ((3x)/2)^2 - ......]`

= `2^(1/3)[1 - x/2 + ((1)/(3)((-2)/3))/2*((9x^2)/4) - ......]`

= `2^(1/3)[1 - x/2 - x^2/4 - ......]`

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Binomial Theorem for Negative Index Or Fraction
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Methods of Induction and Binomial Theorem - Exercise 4.4 [पृष्ठ ८२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board
अध्याय 4 Methods of Induction and Binomial Theorem
Exercise 4.4 | Q 3. (iii) | पृष्ठ ८२

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