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प्रश्न
Simplify:
`(125"x"^-3)^(1/3)`
योग
उत्तर
`(125"x"^-3)^(1/3)`
`=(125)^(1/3) * "x"^(-3xx1/3) ...(because ("a"^"m")^"n" = "a"^("m" xx "n") "and" " a"^"m" xx "a"^"n" = "a"^("m" xx "n"))`
`=(5xx5xx5)^(1/3)."x"^-1`
`= (5^3)^(1/3) * x^-1`
`= (5^cancel(3))^(1/cancel(3)) * x^-1`
= `5x^-1`
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