Question

`(sin(90^circ - θ) sin θ)/tanθ + sin^2 θ` is equal to ______.

विकल्प

• 2

• 1

• 0

• None of these

Answer 1

`(sin(90^circ - θ) sin θ)/tanθ + sin^2 θ` is equal to 1.

Explanation:

We have, `(sin(90^circ - θ) sin θ)/tanθ + sin^2 θ`

= `(cosθ sinθ)/(sinθ/cosθ) + sin^2 θ`

= cos² θ + sin² θ

= 1