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Question
`(sin(90^circ - θ) sin θ)/tanθ + sin^2 θ` is equal to ______.
Options
2
1
0
None of these
MCQ
Fill in the Blanks
Solution
`(sin(90^circ - θ) sin θ)/tanθ + sin^2 θ` is equal to 1.
Explanation:
We have, `(sin(90^circ - θ) sin θ)/tanθ + sin^2 θ`
= `(cosθ sinθ)/(sinθ/cosθ) + sin^2 θ`
= cos2 θ + sin2 θ
= 1
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Trigonometric Functions of Triple Angle
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