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प्रश्न
Solubility product of Ag2CrO4 is 1 × 10−12. What is the solubility of Ag2CrO4 in 0.01 M AgNO3 solution?
उत्तर
Solubility product of Ag2CrO4,
Ksp = 1 × 10−12
\[\ce{\underset{(s)}{Ag2CrO4_{(s)}} ⇌ \underset{(2s)}{2Ag^+_{( aq)}} + \underset{(s)}{CrO^{2-}_{4(aq)}}}\]
\[\ce{\underset{(0.01 M)}{AgNO3_{(s)}} ⇌ \underset{(0.01 M)}{Ag^+_{( aq)}} + \underset{(0.01 M)}{NO^-_{3(aq)}}}\]
[Ag+] = 2s + 0.01
0.01 >> 2s
∴ [Ag+] = 0.01 M
\[\ce{[CrO^{2-}_4]}\] = s
Ksp = \[\ce{[Ag^+]^2 [CrO^{2-}_4]}\]
1 × 10−12 = (0.01)2 (s)
(s) = `(1 xx 10^-12)/((10^-2)^2)`
= `(10 xx 10^-12)/(10^-4)`
= 1 × 10−8 M
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