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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Solubility product of Ag2CrO4 is 1 × 10−12. What is the solubility of Ag2CrO4 in 0.01 M AgNO3 solution? - Chemistry

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Question

Solubility product of Ag2CrO4 is 1 × 10−12. What is the solubility of Ag2CrO4 in 0.01 M AgNO3 solution?

Numerical

Solution

Solubility product of Ag2CrO4,

Ksp = 1 × 10−12

\[\ce{\underset{(s)}{Ag2CrO4_{(s)}} ⇌ \underset{(2s)}{2Ag^+_{( aq)}} + \underset{(s)}{CrO^{2-}_{4(aq)}}}\]

\[\ce{\underset{(0.01 M)}{AgNO3_{(s)}} ⇌ \underset{(0.01 M)}{Ag^+_{( aq)}} + \underset{(0.01 M)}{NO^-_{3(aq)}}}\]

[Ag+] = 2s + 0.01

0.01 >> 2s

∴ [Ag+] = 0.01 M

\[\ce{[CrO^{2-}_4]}\] = s

Ksp = \[\ce{[Ag^+]^2 [CrO^{2-}_4]}\]

1 × 10−12 = (0.01)2 (s)

(s) = `(1 xx 10^-12)/((10^-2)^2)`

 = `(10 xx 10^-12)/(10^-4)`

= 1 × 10−8 M

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Chapter 8: Ionic Equilibrium - Evaluation [Page 31]

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Samacheer Kalvi Chemistry - Volume 1 and 2 [English] Class 12 TN Board
Chapter 8 Ionic Equilibrium
Evaluation | Q 19. | Page 31
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