Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation using formula method only
`"x"^2 + 1/2 "x" = 3`
उत्तर
`"x"^2 + 1/2 "x" = 3`
2x2 + x = 6
2x2 + x - 6 = 0
a = 2 ; b = 1 ; c = -6
D = b2 - 4ac
= (1)2 - 4(2)(-6)
= 1 + 48
= 49
x = `(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(-1 +- sqrt 49)/4`
x = `(- 1 + 7)/4` , x = `(- 1 - 7)/4`
x = `6/4` , x = `-8/4`
x = `3/2` , x = - 2
APPEARS IN
संबंधित प्रश्न
If x=−`1/2`, is a solution of the quadratic equation 3x2+2kx−3=0, find the value of k
Find the nature of the roots of the following quadratic equation. If the real roots exist, find them:
`3x^2 - 4sqrt3x + 4 = 0`
If p, q are real and p ≠ q, then show that the roots of the equation (p − q) x2 + 5(p + q) x− 2(p − q) = 0 are real and unequal.
Find the value of the discriminant in the following quadratic equation :
10 x - `1/x` = 3
Solve the following quadratic equation using formula method only
`3"x"^2 - 5"x" + 25/12 = 0 `
Solve the following quadratic equation using formula method only
25x2 + 30x + 7 = 0
In the quadratic equation kx2 − 6x − 1 = 0, determine the values of k for which the equation does not have any real root.
Solve for x : `9^(x + 2) -6.3^(x + 1) + 1 = 0`.
Find the discriminant of the following equations and hence find the nature of roots: 16x2 - 40x + 25 = 0
The roots of the quadratic equation `1/("a" + "b" + "x") = 1/"a" + 1/"b" + 1/"x"`, a + b ≠ 0 is:
