Advertisements
Advertisements
प्रश्न
Solve the following quadratic equations by factorization:
`4sqrt3x^2+5x-2sqrt3=0`
उत्तर
We have been given
`4sqrt3x^2+5x-2sqrt3=0`
`4sqrt3x^2+8x-3x-2sqrt3=0`
`4x(sqrt3x+2)-sqrt3(sqrt3x+2)=0`
`(sqrt3x+2)(4x-sqrt3)=0`
Therefore,
`sqrt3x+2=0`
`sqrt3x=-2`
`x=-2/sqrt3`
or,
`4x-sqrt3=0`
`4x=sqrt3`
`xsqrt3/4`
Hence, `x=-2/sqrt3` or `xsqrt3/4`
APPEARS IN
संबंधित प्रश्न
Find the consecutive numbers whose squares have the sum 85.
The sum of the squares of the two consecutive odd positive integers as 394. Find them.
The sum of the squares of three consecutive natural numbers as 149. Find the numbers
Sum of the areas of two squares is 640 m2. If the difference of their perimeters is 64 m. Find the sides of the two squares.
If the equation ax2 + 2x + a = 0 has two distinct roots, if
Solve the following equation: 4x2 - 13x - 12 = 0
Solve the following quadratic equation using formula method only
x2 - 6x + 4 = 0
Solve the following quadratic equation by factorisation method:
`x/(x + 1) + (x + 1)/x = (34)/(15') x ≠ 0, x ≠ -1`
Sum of two natural numbers is 8 and the difference of their reciprocal is 2/15. Find the numbers.
If the sum of the roots of the quadratic equation ky2 – 11y + (k – 23) = 0 is `13/21` more than the product of the roots, then find the value of k.
