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Question
Solve the following quadratic equations by factorization:
`4sqrt3x^2+5x-2sqrt3=0`
Solution
We have been given
`4sqrt3x^2+5x-2sqrt3=0`
`4sqrt3x^2+8x-3x-2sqrt3=0`
`4x(sqrt3x+2)-sqrt3(sqrt3x+2)=0`
`(sqrt3x+2)(4x-sqrt3)=0`
Therefore,
`sqrt3x+2=0`
`sqrt3x=-2`
`x=-2/sqrt3`
or,
`4x-sqrt3=0`
`4x=sqrt3`
`xsqrt3/4`
Hence, `x=-2/sqrt3` or `xsqrt3/4`
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