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प्रश्न
Solve the following simultaneous equation graphically.
5x – 6y + 30 = 0 ; 5x + 4y – 20 = 0
आलेख
उत्तर
Step 1: Rewrite the Equations in Slope-Intercept Form
First, we need to convert each equation to the slope-intercept form (y = mx + b) to facilitate graphing.
Equation 1: 5x − 6y + 30 = 0
Solve for y:
5x − 6y + 30 = 0
−6y = −5x − 30
y = `5/6x` + 5
Equation 2: 5x + 4y − 20 = 0
Solve for y:
5x + 4y − 20 = 0
4y = `-5/4x` + 20
y = `-5/4x` + 5
Now we have the equations in the slope-intercept form:
y = `5/6x` + 5
Step 2: Plot the Equations on a Graph
To plot these lines, we need to find the points where they intersect the x-axis and y-axis.
Equation 1: y = `5/6x` + 5
When x = 0:
y = `5/6` (0) + 5 = 5
So, the y-intercept is (0,5).
When y = 0:
0 = `5/6x` + 5
`5/6x` = −5
x = −6
So, the x-intercept is (−6,0).
Equation 2: y = −`5/4x` + 5
When x = 0:
y = −`5/4`(0) + 5 = 5
So, the y-intercept is (0,5).
When y = 0:
0 = −`5/4x` + 5
− `5/4x` = −5
x = 4
So, the x-intercept is (4,0).
Step 3: Draw the Lines on the Graph
Line 1: y = `5/6x` + 5
Passes through (0,5) and (−6,0)
Line 2: y=−`5/4x`+5
Passes through (0,5) and (4,0)
Step 4: Find the Intersection Point
Plot both lines on the same graph. The intersection point of the lines is the solution to the simultaneous equations.
The lines intersect at (0,5).
Step 5: Verify the Solution
Verify the intersection point by substituting (0,5) into the original equations.
For 5x − 6y + 30 = 0:
5(0) − 6(5) + 30 = 0
−30 + 30 = 0
0 = 0
For 5x + 4y − 20 = 0:
5(0) + 4(5) − 20 = 0
20 − 20 = 0
0 = 0
Both equations are satisfied by the point (0,5).
The solution to the simultaneous equations 5x − 6y + 30 = 0 and 5x + 4y − 20 = 0 is: (0,5)
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