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प्रश्न
Solve for x : ` ( log 128) / ( log 32 ) ` = x
उत्तर
` ( log 128 ) / ( log 32 ) ` = x
`=> x =( log 128 )/ ( log 32 )`
`=> x= (log 2xx 2xx 2xx 2xx 2xx 2xx 2)/ (log 2xx 2xx 2xx 2xx 2 ) `
`=> x = log 2^7 / log2^5`
`=> x = ( 7 log 2 )/ ( 5 log 2 ) ` ... [ n loga m = loga mn ]
` => x = ( 7 ) / ( 5 )`
⇒ x = 1.4
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