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प्रश्न
Solve for x:
log(x - 1) + log (x + 1) = log21
योग
उत्तर
log (x - 1) + log(x + 1) = log21
⇒ log [(x - 1) (x + 1)] = 0
⇒ log [(x2 - 1)] = log 1
⇒ x2 - 1 = 1
⇒ x2 = 1 + 1
⇒ x2 = 2
⇒ x = `+- sqrt2`
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Interchanging Logarithmic and Exponential Forms
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