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प्रश्न
Solve the following equation by the trial-and-error method: `x/3`= 4
उत्तर
`x/3`= 4
Since R.H.S. is a natural number so L.H.S. must also be a natural number. Thus, x has to be a multiple of 3.
| x | L.H.S. | R.H.S. | Is L.H.S. = R.H.S.? |
| 3 | `3/3`= 1 | 4 | No |
| 6 | `6/3` = 2 | 4 | No |
| 9 | `9/3` = 3 | 4 | No |
| 12 | `12/3` = 4 | 4 | Yes |
∴ x = 12
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