Advertisements
Advertisements
Question
Solve the following equation by the trial-and-error method: `x/3`= 4
Solution
`x/3`= 4
Since R.H.S. is a natural number so L.H.S. must also be a natural number. Thus, x has to be a multiple of 3.
| x | L.H.S. | R.H.S. | Is L.H.S. = R.H.S.? |
| 3 | `3/3`= 1 | 4 | No |
| 6 | `6/3` = 2 | 4 | No |
| 9 | `9/3` = 3 | 4 | No |
| 12 | `12/3` = 4 | 4 | Yes |
∴ x = 12
APPEARS IN
RELATED QUESTIONS
Check whether the value given in the bracket is a solution to the given equation or not:
n + 5 = 19 (n = 1)
Write equation for the following statement:
If you take away 6 from 6 times y, you get 60.
Add 3x, 7x
Simplify:
5a − [a2 − {2a(1 − a + 4a2) − 3a(a2 − 5a − 3)}] −8a
Write the following statement as an equation:
5 subtracted from thrice a number is 16.
Write a statement for the equation, given below:
x − 7 = 14
Solve the following equation and verify the answer:
3x − 5 = 13
A wire of length 86 cm is bent in the form of a rectangle such that its length is 7 cm more than its breadth. Find the length and the breadth of the rectangle so formed.
The distance (in km) travelled in h hours at a constant speed of 40 km per hour is ______.
A bus travels at v km per hour. It is going from Daspur to Beespur. After the bus has travelled 5 hours, Beespur is still 20 km away. What is the distance from Daspur to Beespur? Express it using v.
