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Question
Solve the following equation by the trial-and-error method: 2x − 3 = 9
Solution
2x − 3 = 9
We try several values of x until we get the L.H.S. equal to the R.H.S.
| x | L.H.S. | R.H.S. | Is L.H.S. = R.H.S.? |
| 1 | 2 × 1 − 3 = −1 | 9 | No |
| 2 | 2 × 2 − 3 = 1 | 9 | No |
| 3 | 2 × 3 − 3 = 3 | 9 | No |
| 4 | 2 × 4 − 3 = 5 | 9 | No |
| 5 | 2 × 5 − 3 = 7 | 9 | No |
| 6 | 2 × 6 − 3 = 9 | 9 | Yes |
∴ x = 6
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