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Solve the following equationssin² x – 5 sin x + 4 = 0 - Mathematics

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प्रश्न

Solve the following equations
sin² x – 5 sin x + 4 = 0

योग

उत्तर

sin2x – 5sinx + 4 = 0

Let y = sin x

(y2 – 5y + 4) = 0

(y – 1)(y – 4) = 0

(y – 1) = o or (y – 4) = 0

y = 1 or y = 4

sin x = 1 or sin x = 4  .....[not possible since sin x ≤ 1]

sin x = `sin  pi/2`

x = nπ + (– 1)n α, n ∈ z.

x = `"n"pi + (- 1)^"n"  pi/2`

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Polynomial Equations with No Additional Information
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Theory of Equations - Exercise 3.5 [पृष्ठ १२४]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 3 Theory of Equations
Exercise 3.5 | Q 1. (i) | पृष्ठ १२४
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