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Question
Solve the following equations
sin² x – 5 sin x + 4 = 0
Solution
sin2x – 5sinx + 4 = 0
Let y = sin x
(y2 – 5y + 4) = 0
(y – 1)(y – 4) = 0
(y – 1) = o or (y – 4) = 0
y = 1 or y = 4
sin x = 1 or sin x = 4 .....[not possible since sin x ≤ 1]
sin x = `sin pi/2`
x = nπ + (– 1)n α, n ∈ z.
x = `"n"pi + (- 1)^"n" pi/2`
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