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प्रश्न
Solve the following L.P.P. graphically:
Minimise Z = 6x + 3y
Subject to constraints
4x + y ≥ 80;
x + 5y ≥ 115;
3x + 2y ≤ 150
x, y ≥ 0
योग
उत्तर
Min Z = 6x + 3y
S.T.C.
4x + y ≥ 80;
x + 5y ≥ 115;
3x + 2y ≤ 150
The feasible region determined by the constraints is given below:
| Corner Points | coordinates | Z = 6x + 3y |
| A | (15, 20) | 150 Minimum |
| B | (2, 72) | 228 |
| C | (40, 15) | 285 |
Hence, the minimum value of Z is 150 attains at (15, 20).
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