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Solve the following problem : Following table shows the all India infant mortality rates (per ‘000) for years 1980 to 2010.Fit a trend line to the above data by graphical method. - Mathematics and Statistics

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प्रश्न

Solve the following problem :

Following table shows the all India infant mortality rates (per ‘000) for years 1980 to 2010.

Year 1980 1985 1990 1995 2000 2005 2010
IMR 10 7 5 4 3 1 0

Fit a trend line to the above data by graphical method.

आलेख

उत्तर

Taking year on X-axis and mortality rate on Y-axis, we plot the points for mortality rate corresponding to years. Joining these points we get the graph of time series. We fit the trend line as shown in the following graph.

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Measurement of Secular Trend
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Time Series - Miscellaneous Exercise 4 [पृष्ठ ७०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Commerce) [English] 12 Standard HSC Maharashtra State Board
अध्याय 4 Time Series
Miscellaneous Exercise 4 | Q 4.16 | पृष्ठ ७०

संबंधित प्रश्न

Obtain the trend line for the above data using 5 yearly moving averages.


Fit a trend line to the data in Problem 7 by the method of least squares. Also, obtain the trend value for the year 1990.


Choose the correct alternative :

We can use regression line for past data to forecast future data. We then use the line which_______.


State whether the following is True or False :

Moving average method of finding trend is very complicated and involves several calculations.


State whether the following is True or False :

Least squares method of finding trend is very simple and does not involve any calculations.


Solve the following problem :

Fit a trend line to data in Problem 4 by the method of least squares.


Solve the following problem :

Obtain trend values for the data in Problem 7 using 4-yearly moving averages.


Solve the following problem :

Following data shows the number of boxes of cereal sold in years 1977 to 1984.

Year 1977 1978 1979 1980 1981 1982 1983 1984
No. of boxes in ten thousand 1 0 3 8 10 4 5 8

Fit a trend line to the above data by graphical method.


Solve the following problem :

Obtain trend values for data in Problem 10 using 3-yearly moving averages.


Choose the correct alternative:

Moving averages are useful in identifying ______.


The simplest method of measuring trend of time series is ______


The method of measuring trend of time series using only averages is ______


State whether the following statement is True or False: 

Moving average method of finding trend is very complicated and involves several calculations


Following table shows the amount of sugar production (in lac tons) for the years 1971 to 1982

Year 1971 1972 1973 1974 1975 1976
Production 1 0 1 2 3 2
Year 1977 1978 1979 1980 1981 1982
Production 4 6 5 1 4 10

Fit a trend line by the method of least squares


The following table shows the production of gasoline in U.S.A. for the years 1962 to 1976.

Year 1962 1963 1964 1965 1966 1967 1968 1969
Production
(million barrels)
0 0 1 1 2 3 4 5
Year 1970 1971 1972 1973 1974 1975 1976  
Production
(million barrels)
6 7 8 9 8 9 10  
  1. Obtain trend values for the above data using 5-yearly moving averages.
  2. Plot the original time series and trend values obtained above on the same graph.

The publisher of a magazine wants to determine the rate of increase in the number of subscribers. The following table shows the subscription information for eight consecutive years:

Years 1976 1977 1978 1979
No. of subscribers
(in millions)
12 11 19 17
Years 1980 1981 1982 1983
No. of subscribers
(in millions)
19 18 20 23

Fit a trend line by graphical method.


Following table gives the number of road accidents (in thousands) due to overspeeding in Maharashtra for 9 years. Complete the following activity to find the trend by the method of least squares.

Year 2008 2009 2010 2011 2012 2013 2014 2015 2016
Number of accidents 39 18 21 28 27 27 23 25 22

Solution:

We take origin to 18, we get, the number of accidents as follows:

Year Number of accidents xt t u = t - 5 u2 u.xt
2008 21 1 -4 16 -84
2009 0 2 -3 9 0
2010 3 3 -2 4 -6
2011 10 4 -1 1 -10
2012 9 5 0 0 0
2013 9 6 1 1 9
2014 5 7 2 4 10
2015 7 8 3 9 21
2016 4 9 4 16 16
  `sumx_t=68` - `sumu=0` `sumu^2=60` `square`

The equation of trend is xt =a'+ b'u.

The normal equations are,

`sumx_t=na^'+b^'sumu             ...(1)`

`sumux_t=a^'sumu+b^'sumu^2      ...(2)`

Here, n = 9, `sumx_t=68,sumu=0,sumu^2=60,sumux_t=-44`

Putting these values in normal equations, we get

68 = 9a' + b'(0)     ...(3)

∴ a' = `square`

-44 = a'(0) + b'(60)          ...(4)

∴ b' = `square`

The equation of trend line is given by

xt = `square`


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