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Obtain the trend line for the above data using 5 yearly moving averages. - Mathematics and Statistics

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प्रश्न

Obtain the trend line for the above data using 5 yearly moving averages.

योग

उत्तर

Construct the following table to obtain 5 yearly moving averages in data of problem 1.

Year T Production yt
(in' 000 tonnes)
5 – yearly moving total 5 – yearly moving averages trend value
1962 0
1963 0
1964 1 6 1.2
1965 1 8 1.6
1966 4 12 2.4
1967 2 20 4
1968 4 26 5.2
1969 9 32 6.4
1970 7 38 7.6
1971 10
1972 8
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Measurement of Secular Trend
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अध्याय 4: Time Series - Exercise 4.1 [पृष्ठ ६६]

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संबंधित प्रश्न

Obtain the trend values for the above data using 3-yearly moving averages.


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We can use regression line for past data to forecast future data. We then use the line which_______.


Choose the correct alternative :

Which of the following is a major problem for forecasting, especially when using the method of least squares?


Fill in the blank :

The complicated but efficient method of measuring trend of time series is _______.


State whether the following is True or False :

All the three methods of measuring trend will always give the same results.


Solve the following problem :

Fit a trend line to data in Problem 4 by the method of least squares.


Solve the following problem :

Obtain trend values for the data in Problem 7 using 4-yearly moving averages.


Solve the following problem :

Following data shows the number of boxes of cereal sold in years 1977 to 1984.

Year 1977 1978 1979 1980 1981 1982 1983 1984
No. of boxes in ten thousand 1 0 3 8 10 4 5 8

Fit a trend line to the above data by graphical method.


Solve the following problem :

Obtain trend values for data in Problem 16 using 3-yearly moving averages.


Obtain trend values for data in Problem 19 using 3-yearly moving averages.


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The secular trend component of time series represents irregular variations


State whether the following statement is True or False: 

Moving average method of finding trend is very complicated and involves several calculations


The following table gives the production of steel (in millions of tons) for years 1976 to 1986.

Year 1976 1977 1978 1979 1980 1981 1982 1983 1984 1985 1986
Production 0 4 4 2 6 8 5 9 4 10 10

Obtain the trend value for the year 1990


Use the method of least squares to fit a trend line to the data given below. Also, obtain the trend value for the year 1975.

Year 1962 1963 1964 1965 1966 1967 1968 1969
Production
(million barrels)
0 0 1 1 2 3 4 5
Year 1970 1971 1972 1973 1974 1975 1976  
Production
(million barrels)
6 8 9 9 8 7 10  

Obtain trend values for data, using 3-yearly moving averages
Solution:

Year IMR 3 yearly
moving total
3-yearly moving
average

(trend value)
1980 10
1985 7 `square` 7.33
1990 5 16 `square`
1995 4 12 4
2000 3 8 `square`
2005 1 `square` 1.33
2010 0

Fit equation of trend line for the data given below.

Year Production (y) x x2 xy
2006 19 – 9 81 – 171
2007 20 – 7 49 – 140
2008 14 – 5 25 – 70
2009 16 – 3 9 – 48
2010 17 – 1 1 – 17
2011 16 1 1 16
2012 18 3 9 54
2013 17 5 25 85
2014 21 7 49 147
2015 19 9 81 171
Total 177 0 330 27

Let the equation of trend line be y = a + bx   .....(i)

Here n = `square` (even), two middle years are `square` and 2011, and h = `square`

The normal equations are Σy = na + bΣx

As Σx = 0, a = `square`

Also, Σxy = aΣx + bΣx2

As Σx = 0, b = `square`

Substitute values of a and b in equation (i) the equation of trend line is `square`

To find trend value for the year 2016, put x = `square` in the above equation.

y = `square`


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Years 1966 1967 1968 1969 1970
Gross Capital information 20 25 25 30 35
Years 1971 1972 1973 1974 1975
Gross Capital information 30 45 40 55 65

Obtain trend values using 5-yearly moving values.


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