Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation by factorization method.
3p2 + 8p + 5 = 0
उत्तर
3p2 + 8p + 5 = 0
∴ 3p2 + 5p + 3p + 5 = 0
| 3 × 5 = | 15 |
| 5 3 | |
| 5 × 3 = 15 5 + 3 = 8 |
∴ p(3p + 5) + 1(3p + 5) = 0
∴ (3p + 5) (p + 1) = 0
By using the property, if the product of two numbers is zero, then at least one of them is zero, we get
3p + 5 = 0 or p + 1 = 0
∴ 3p = – 5 or p = – 1
∴ p = `(-5)/3` or p = – 1
∴ The roots of the given quadratic equation are `(-5)/3` and – 1
APPEARS IN
संबंधित प्रश्न
Find x in terms of a, b and c: `a/(x-a)+b/(x-b)=(2c)/(x-c)`
Solve the following quadratic equations by factorization:
4x2 + 5x = 0
The sum of two numbers is 18. The sum of their reciprocals is 1/4. Find the numbers.
The product of Ramu's age (in years) five years ago and his age (in years) nice years later is 15. Determine Ramu's present age.
Solve the following quadratic equations by factorization:
`4/(x+2)-1/(x+3)=4/(2x+1)`
Solve the following quadratic equation by factorization.
`2"x"^2 - 2"x" + 1/2 = 0`
If \[1 + \sqrt{2}\] is a root of a quadratic equation will rational coefficients, write its other root.
The number of quadratic equations having real roots and which do not change by squaring their roots is
Solve the following equation: 2x2 - x - 6 = 0
Solve the following equation: `("a+b")^2 "x"^2 - 4 "abx" - ("a - b")^2 = 0`
Solve the following equation: a2b2x2 + b2x - a2x - 1 = 0
The product of a girl's age five years ago and her age 3 years later is 105. Find her present age.
The hypotenuse of a grassy land in the shape of a right triangle is 1 m more than twice the shortest side. If the third side is 7m more than the shortest side, find the sides of the grassy land.
Solve equation using factorisation method:
`6/x = 1 + x`
Solve equation using factorisation method:
2(x2 – 6) = 3(x – 4)
Solve the following quadratic equation using factorization method:
`"x"^2-11"x"+24=0`
A two digit positive number is such that the product of its digits is 6. If 9 is added to the number, the digits interchange their places. Find the number.
Find two consecutive even natural numbers such that the sum of their squares is 340.
Sum of two natural numbers is 8 and the difference of their reciprocal is 2/15. Find the numbers.
2x articles cost Rs. (5x + 54) and (x + 2) similar articles cost Rs. (10x – 4), find x.
