Advertisements
Advertisements
प्रश्न
The product of a girl's age five years ago and her age 3 years later is 105. Find her present age.
उत्तर
Let the present age of the Girl be G year. Then, as per the question description,
(G - S)(G + 3) = 105
⇒ G2 - 2G - 120 = 0
⇒ G2 -12G + 10G - 120 = 0
⇒ G (G - 12) +10 (G - 12) = 0
⇒ G=12 , G = -10 (Agecannotbe negative)
⇒ G=12 Years
APPEARS IN
संबंधित प्रश्न
Solve the equation `4/x-3=5/(2x+3); xne0,-3/2` for x .
If 2 is a root of the equation x2 + ax + 12 = 0 and the quadratic equation x2 + ax + q = 0 has equal roots, then q =
Solve the following equation: `("x" + 3)/("x" + 2) = (3"x" - 7)/(2"x" - 3)`
The sum of the square of 2 positive integers is 208. If the square of larger number is 18 times the smaller number, find the numbers.
The sum of the square of two numbers is 233. If one of the numbers is 3 less than twice the other number. Find the numbers.
The area of right-angled triangle is 600cm2. If the base of the triangle exceeds the altitude by 10cm, find the dimensions of the triangle.
A two digit positive number is such that the product of its digits is 6. If 9 is added to the number, the digits interchange their places. Find the number.
Solve the following equation by factorization
3(y2 – 6) = y(y + 7) – 3
Solve the following equation by factorization
5x2 – 8x – 4 = 0 when x∈Q
In a certain positive fraction, the denominator is greater than the numerator by 3. If 1 is subtracted from both the numerator and denominator, the fraction is decreased by `(1)/(14)`. Find the fraction.
