Advertisements
Advertisements
Question
The product of a girl's age five years ago and her age 3 years later is 105. Find her present age.
Solution
Let the present age of the Girl be G year. Then, as per the question description,
(G - S)(G + 3) = 105
⇒ G2 - 2G - 120 = 0
⇒ G2 -12G + 10G - 120 = 0
⇒ G (G - 12) +10 (G - 12) = 0
⇒ G=12 , G = -10 (Agecannotbe negative)
⇒ G=12 Years
APPEARS IN
RELATED QUESTIONS
Solve the equation `3/(x+1)-1/2=2/(3x-1);xne-1,xne1/3,`
Determine two consecutive multiples of 3, whose product is 270.
Solve the following quadratic equations by factorization:
`5/(x - 2) - 3/(x + 6) = 4/x`
Solve the following quadratic equation by factorisation.
x2 – 15x + 54 = 0
Find the values of k for which the roots are real and equal in each of the following equation:
\[4 x^2 + px + 3 = 0\]
Solve equation using factorisation method:
(x + 1)(2x + 8) = (x + 7)(x + 3)
Car A travels x km for every litre of petrol, while car B travels (x + 5) km for every litre of petrol.
If car A use 4 litre of petrol more than car B in covering the 400 km, write down and equation in x and solve it to determine the number of litre of petrol used by car B for the journey.
Solve the following equation by factorization
5x2 – 8x – 4 = 0 when x∈Q
If x = p is a solution of the equation x(2x + 5) = 3, then find the value of p.
The polynomial equation x(x + 1) + 8 = (x + 2) (x – 2) is:
