Advertisements
Advertisements
प्रश्न
Solve the following riddles, you may yourself construct such riddles.
Who am I? |
For each day of the week Make an upcount from me If you make no mistake You will get twenty three! |
उत्तर
23 was the result when the old number was up counted on Sunday.
22 was the result when the old number was up counted on Saturday.
21 was the result when the old number was up counted on Friday.
20 was the result when the old number was up counted on Thursday.
19 was the result when the old number was up counted on Wednesday.
18 was the result when the old number was up counted on Tuesday.
17 was the result when the old number was up counted on Monday.
Therefore, number taken at the start = 17 − 1 = 16.
APPEARS IN
संबंधित प्रश्न
Complete the last column of the table.
Equation | Value | Say, whether the Equation is Satisfied. (Yes/No) |
`m/3 = 2` | m = 6 |
Write equation for the following statement:
The number b divided by 5 gives 6.
Solve the following equation by the trial-and-error method: `x/3`= 4
Solve the following equation by the trial-and-error method: 2x − 3 = 9
A bag contains 25-paisa and 50-paisa coins whose total value is Rs 30. If the number of 25-paisa coins is four times that of 50-paisa coins, find the number of each type of coins.
Write 'T' for true and 'F' for false for the statement given below:
8 − x = 5 ⇒ x = 3.
When a number is divided by 8, the result is –3. The number is ______.
Anushka and Aarushi are friends. They have equal amount of money in their pockets. Anushka gave `1/3` of her money to Aarushi as her birthday gift. Then Aarushi gave a party at a restaurant and cleared the bill by paying half of the total money with her. If the remaining money in Aarushi’s pocket is Rs.1600, find the sum gifted by Anushka.
The distance (in km) travelled in h hours at a constant speed of 40 km per hour is ______.
x exceeds 3 by 7, can be represented as ______.