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प्रश्न
Solve the following simultaneous equations.
`2/(x + y) - 3/(x - y)` = 15; `8/(x + y) + 5/(x - y)` = 77
उत्तर
`2/(x + y) - 3/(x - y)` = 15 ....(i)
`8/(x + y) + 5/(x - y)` = 77 ....(ii)
Replacing `(1/(x + y))` by a and `1/(x - y)` by b in equation (i) and equation (ii), we get
2a - 3b = 15 ....(iii)
8a + 5b = 77 ....(iv)
Multiplying equation (iii) by 5 and equation (iv) by 3
10a – 15b = 75 ....(v)
24a + 15b = 231 ...(vi)
Now adding equations (v) and (vi), we get
⇒ 10a + 24a = 75 + 231
⇒ 34a = 306
∴ a = `306/34`
∴ a = 9
Substituting, a = 9 in equation (iii), we get
⇒ 2(9) – 3b = 15
⇒ 3b = 18 – 15
∴ 3b = 3
∴ b = 1
By reversing the values of a and b, we get
`1/(x + y)` = 9 and `1/(x - y)` = 1
∴ x + y = 9 ....(vii)
And x – y = 1 ....(viii)
Adding equations (vii) and (viii), we get
∴ 2x = 10
x = 5
Substituting, x = 5 in equations (vii), we get
5 + y = 9
∴ y = 4
As a result, the above equation's solution is x = 5, y = 4.