Advertisements
Advertisements
प्रश्न
Solve the inequation:
– 8 ≤ – (3x – 5) < 13
उत्तर
– 8 ≤ – (3x – 5) < 13
Multiplying by − 1 throughout (so inequality sign changes)
∴ 8 ≥ 3x – 5 > – 13
i.e., – 13 < 3x – 5 ≤ 8
Adding 5 on both the sides, we get
– 8 < 3x ≤ 13
Dividing, by 3 on both sides, we get
∴ `-8/3 < "x" ≤ 13/3`
i.e., x takes all real values between `-8/3` and `13/3` including `13/3`.
∴ the solution set is `[-8/3,13/3]`
APPEARS IN
संबंधित प्रश्न
Solve the following inequation:
7x – 25 ≤ – 4
Solve the following inequation: `0 < ("x" - 5)/4 < 3`
Solve the following inequation: |7x – 4| < 10
Solve the inequation:
4 – 2x < 3(3 – x)
Solve the inequation:
`3/4 "x" - 6 ≤ "x" - 7`
Solve the inequation:
`– 1 < 3 – "x"/5 ≤ 1`
Solve the inequation:
2|4 – 5x| ≥ 9
Solve the inequation:
|2x + 7| ≤ 25
The region represented by {z = x + iy ∈ C : |z| – Re(z) ≤ 1} is also given by the inequality is ______.
Consider the two sets : A = {m ∈ R : both the roots of x2 – (m + 1)x + m + 4 = 0 are real} and B = [–3, 5). Which of the following is not true?
Let S be the set of all real roots of the equation, 3x(3x – 1) + 2 = |3x – 1| + |3x – 2|. Then S ______.
Let Z be the set of integers. lf A = `{x ∈ Z: 2^((x + 2)(x^2 – 5x + 6)) = 1}` and B = {x ∈ Z: –3 < 2x – 1 < 9}, then the number of subsets of the set A × B, is ______.
All the-pairs (x, y) that satisfy the inequality `2^sqrt(sin^2x - 2sinx + 5), 1/(4^(sin^2y)) ≤ 1` also satisfy the equation ______.
