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प्रश्न
Solve for x: `3x^2-2sqrt3x+2=0`
उत्तर
The given quadratic equation is`3x^2-2sqrt3x+2=0`
Comparing with the quadratic equation ax2 + bx + c = 0, we have
`a=3,b=-2sqrt3,c=2`
Discriminant of the given quadratic equation,
`D=b^2-4ac=(2sqrt6)^2-4xx3xx2=24-24=0`
`therefore x= (-(-2sqrt3)+-sqrt3)/(2xx3)` `[thereforex=(-b+-sqrtD)/(2a)]`
`rArrx=(2sqrt6)/6`
`rArrx=(sqrt6)/3`
Thus, the solution of the given quadratic equation is `x=(sqrt6)/3`
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