Advertisements
Advertisements
प्रश्न
The hypotenuse of a right triangle is 25 cm. The difference between the lengths of the other two sides of the triangle is 5 cm. Find the lengths of these sides.
उत्तर
Let the length of one side of right triangle be = x cm then other side be = (x + 5) cm
And given that hypotenuse = 25 cm
As we know that by Pythagoras theorem,
x2 + (x + 5)2 = (25)2
x2 + x2 + 10x + 25 = 625
2x2 +10x + 25 - 625 = 0
2x2 + 10x - 600 = 0
x2 + 5x - 600 = 0
x2 - 15x + 20x - 600 = 0
x(x - 15) + 20(x - 15) = 0
(x - 15)(x + 20) = 0
So, either
x - 15 = 0
x = 15
Or
x + 20 = 0
x = -20
But the side of right triangle can never be negative
Therefore, when x = 15 then
x + 5 = 15 + 5 = 20
Hence, length of one side of right triangle be 15 cm then other side be 20 cm.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation for x: x2 – 2ax – (4b2 – a2) = 0
Solve the following quadratic equations by factorization:
4x2 + 5x = 0
Solve the following quadratic equations by factorization:
`1/(x-2)+2/(x-1)=6/x` , x ≠ 0
Some students planned a picnic. The budget for food was Rs. 500. But, 5 of them failed to go and thus the cost of food for each member increased by Rs. 5. How many students attended the picnic?
Solve:
(a + b)2x2 – (a + b)x – 6 = 0; a + b ≠ 0
In the following determine the set of values of k for which the given quadratic equation has real roots: \[2 x^2 + x + k = 0\]
If the roots of the equations \[\left( a^2 + b^2 \right) x^2 - 2b\left( a + c \right)x + \left( b^2 + c^2 \right) = 0\] are equal, then
If x = 1 is a common roots of the equations ax2 + ax + 3 = 0 and x2 + x + b = 0, then ab =
Sum of two natural numbers is 8 and the difference of their reciprocal is 2/15. Find the numbers.
There are three consecutive positive integers such that the sum of the square of the first and the product of other two is 154. What are the integers?