Advertisements
Advertisements
प्रश्न
Solve for x
`(x - 1)/(2x + 1) + (2x + 1)/(x - 1) = 2, "where x" != -1/2, 1`
उत्तर
`(x - 1)/(2x + 1) + (2x + 1)/(x - 1) = 2`
`=>((x - 1)^2 + (2x + 1)^2)/((2x + 1)(x + 1)) = 2`
`=> (x^2 + 1 -2x + 4x^2 + 1 + 4x)/(2x^2 - 2x + x - 1) = 2`
`=> 5x^2 + 2x + 2 = 4x^2 - 2x - 2`
`=> x^2 + 4x + 4 = 0`
`=> (x + 2)^2 = 0`
⇒ x= -2 , -2
APPEARS IN
संबंधित प्रश्न
Find the roots of the following quadratic equation by factorisation:
x2 – 3x – 10 = 0
Solve the following quadratic equations by factorization:
(x − 4) (x + 2) = 0
Solve the following quadratic equations by factorization:
(a + b)2x2 - 4abx - (a - b)2 = 0
The sum of a number and its square is 63/4. Find the numbers.
A two digit number is such that the product of the digits is 16. When 54 is subtracted from the number the digits are interchanged. Find the number
Solve the following quadratic equation by factorisation.
2m (m − 24) = 50
Solve the following quadratic equation by factorisation.
7m2 = 21m
Solve the following equation: 4x2 + 4 bx - (a2 - b2) = 0
Solve the following quadratic equation by factorisation:
2x2 + ax - a2 = 0 where a ∈ R.
Sum of two natural numbers is 8 and the difference of their reciprocal is 2/15. Find the numbers.
