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प्रश्न
Solve:
`x/2 + 5 <= x/3 + 6`, where x is a positive odd integer
उत्तर
`x/2 + 5 <= x/3 + 6`
`x/2 - x/3 <= 6 - 5`
`x/6 <= 1`
`x <= 6`
Since, x is a positive odd integer
∴ Solution set = {1, 3, 5}
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