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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 6

Take (-3)/2"P"+"Q"-"R" from 1/2"P"-1/3"Q"-3/2"R". - Mathematics

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प्रश्न

Take `(-3)/2"p"+"q"-"r"` from `1/2"p"-1/3"q"-3/2"r".`

योग

उत्तर

`(1/2"p"-1/3"q"-3/2"r")-(-3/2"p"+"q"-"r")`

= `1/2"p"-1/3"q"-3/2"r"+3/2"p"-"q"+"r"`

= `1/2"p"+3/2"p"-1/3"q"-"q"-3/2"r"+"r"`

= `(3"p"+9"p"-2"q"-6"q"-9"r"+6"r")/6` ..........[Since L.C.M. = 6]

= `(12"p")/6-(8"q")/6-(3"r")/6`

= `2"p"-4/3"q"-1/2"r"`

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Algebra Terminology - Literal Numbers, Terms, Expressions, Factor, Coefficient, Polynomials, Degree, like and Unlike Terms
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 19: Fundamental Operations (Related to Algebraic Expressions) - Exercise 19 (B)

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सेलिना Mathematics [English] Class 6
अध्याय 19 Fundamental Operations (Related to Algebraic Expressions)
Exercise 19 (B) | Q 5.3
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